Question

The height Hs of the solids of the specimen with respect to weight of dried specimen is _____________

(a) \(H_s=\frac{W_d}{Gρ_w}\)

(b) \(H_s=\frac{W_d}{GAρ_w}\)

(c) \(H_s=\frac{W_d}{GA}\)

(d) \(H_s=\frac{W_d}{Aρ_w}\)

I have been asked this question in an online quiz.

This key question is from Calculation of Voids Ratio and Coefficient of Volume Change in chapter One Dimensional Consolidation of Geotechnical Engineering I

Answer 1

The correct answer is (c) \(H_s=\frac{W_d}{GA}\)

For explanation I would say: Since the height HS of the solids of the specimen is calculated from the expression,

\(H_s=\frac{W_d}{GAρ_w}\) and the dry weight in relation to dry mass is given by,

\(W_d=\frac{M_d}{ρ_w}.\) Therefore, the The height Hs of the solids of the specimen with respect to weight of dried specimen is,

\(H_s=\frac{W_d}{GA}.\)