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For a dry soil mass of 180.4 g, specific gravity 2.68 and cross-sectional area of specimen as 50 cm^2, find the height of solids Hs.

(a) 13.45 mm

(b) 14 mm

(c) 17 mm

(d) 19.5 mm

I got this question during an online interview.

This intriguing question comes from Consolidation Problems topic in chapter One Dimensional Consolidation of Geotechnical Engineering I

1 Answer

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Best answer
The correct answer is (a) 13.45 mm

The best I can explain: Given,

Md=180.4 g

G=2.68

A=50cm^2

Since \(H_s=\frac{M_d}{GAρ_w}\)

\(H_s=\frac{180.4*10}{2.68*50*1}  =13.45mm.\)

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