The correct option is (c) 13.9 hours
For explanation: Given,
d=50 cm
Cv=4×10^-4 cm^2/s
For consolidation of 10%, U<60%
Tv=\(\frac{π}{4} (\frac{v}{100})^2=\frac{π}{4} (\frac{10}{100})^2=0.008\)
Therefore time elapsed \(t_{10}=\frac{(T_v)_{10} d^2}{C_v} = \frac{0.008×(50)^2}{4×10^{-4}} s = 13.9 hours.\)