Right option is (b) 386 days
Explanation: Given, double drainage for both specimen and field,
t1=20 min
d1=24 mm/2 = 2.4 cm/2 = 1.2 cm
d2 =4/2 m 200cm
Since, for same degree of consolidation of 50%, Tv is same,
\(t∝\frac{d^2}{C_r}\)
Therefore, \(\frac{t_2}{t_1} =(\frac{d_2}{d_1})^2\)
So, \(t_2=t_1 (\frac{d_2}{d_1} )^2=20(\frac{200}{1.2})^2=365 \,days.\)