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Two clay layer of A and B of thickness 2cm and 3 cm is load with pressure of 200KN/m^2. If the time taken by soil A to reach 50% consolidation is 1/4^th of that required by soil B to reach 50% consolidation, then find the ratio of coefficients of consolidation.

(a) 2.4432

(b) 1.7778

(c) 4.3312

(d) 5.3489

I have been asked this question during a job interview.

I want to ask this question from Consolidation Problems in chapter One Dimensional Consolidation of Geotechnical Engineering I

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The correct answer is (b) 1.7778

Easiest explanation: Given,

dA=2/2 = 1cm

dB=3/2= 1.5 cm

\(\frac{t_B}{t_A} = \frac{4}{1}\)

The ratio of coefficient of consolidation is, \(\frac{(C_v)_A}{(C_v)_B} \)

\(\frac{(C_v)_A}{(C_v)_B} = \frac{(d_A)^2}{(d_B)^2} × \frac{t_B}{t_A} = \frac{(2/2)^2}{(3/2)^2} × \frac{4}{1}=1.7778.\)

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