The correct answer is (b) 2m
Easiest explanation: Given, the sample has double drainage while the field layer has single drainage.
t1= 20 min
t2= 386 days
d1= 2.4/2 = 1.2 cm
since, \(\frac{t_2}{t_1} =(\frac{d_2}{d_1})^2\)
therefore \(d_2 = d_1 \sqrt{\frac{t_2}{t_1}}=1.2\sqrt{\frac{386×60×24}{20}}=200cm=2m.\)