The correct option is (c) 400cm
For explanation I would say: Given, both the sample and the field layer has single drainage,
t1= 20 min
t2= 386 days
d1= 2.4cm
since, \(\frac{t_2}{t_1} =(\frac{d_2}{d_1})^2\)
therefore \(d_2 = d_1 \sqrt{\frac{t_2}{t_1}}=2.4\sqrt{\frac{386×60×24}{20}}=400cm=4m.\)