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For a dry mass of soil of 180.4g and height of solids as 13.45mm with cross-sectional area as 50cm^2, find the specific gravity of soil.

(a) 2.68

(b) 8.33

(c) 1.64

(d) 5.32

This question was addressed to me in an interview for internship.

The origin of the question is Consolidation Problems in chapter One Dimensional Consolidation of Geotechnical Engineering I

1 Answer

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Best answer
Right option is (a) 2.68

Explanation: Given,

Md=180.4 g

A= 5- cm^2

Hs=13.45 mm

We know that, \(H_s=\frac{M_d}{GAρ_w}\)

\(G=\frac{M_d}{H_s Aρ_w}\)

\(G=\frac{180.4×10}{13.45×50×1}=2.68.\)

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