Right answer is (a) 386 days
To explain I would say: Given, single drainage for both the sample and for the field layer,
t1=20 min
d1=24 mm= 2.4 cm
d2 =4 m = 400cm
Since, for same degree of consolidation of 50%, Tv is same,
\(tâ\frac{d^2}{C_r}\)
Therefore, \(\frac{t_2}{t_1} =(\frac{d_2}{d_1} )^2\)
So, \(t_2=t_1 (\frac{d_2}{d_1})^2=20(\frac{400}{2.4})^2=386 \,days.\)