Right option is (a) 800cm
The best explanation: Given, the sample has single drainage while the field layer has double drainage.
t1= 20 min
t2= 386 days
d1= 2.4 cm
since, \(\frac{t_2}{t_1} =(\frac{d_2}{d_1})^2\)
therefore \(d_2 = d_1 \sqrt{\frac{t_2}{t_1}}=2.4\sqrt{\frac{386×60×24}{20}}=400cm=4m.\)
Since double drainage is allowed in field, the depth is 400×2= 800 cm.