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If height of solids Hs is 6.725mm, mass is 180.4g with specific gravity G=2.68, then final the Cross-sectional area of specimen.

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If height of solids Hs is 6.725mm, mass is 180.4g with specific gravity G=2.68, then final the Cross-sectional area of specimen.

(a) 220 cm^2

(b) 342 cm^2

(c) 100 cm^2

(d) 659 cm^2

I had been asked this question in an interview for internship.

I'd like to ask this question from Consolidation Problems topic in division One Dimensional Consolidation of Geotechnical Engineering I

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Right choice is (c) 100 cm^2

To explain I would say: Given,

Hs=6.725mm

G=2.68

Md=180.4g

Since \(H_s= \frac{M_d}{GH_s ρ_w}\)

\(A=\frac{M_d}{GH_s ρ_w}\)

\(A=\frac{180.4×10}{2.68×6.725×1}=100cm^2.\)

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