Question

If the final height of specimen Hf is 13.45mm and final voids is 0.864, then the change of voids ratio ∆e with respect to ∆H is ____________

(a) ∆e=0.139∆H

(b) ∆e=0.123∆H

(c) ∆e=0.178∆H

(d) ∆e=0.148∆H

I had been asked this question during a job interview.

The query is from Consolidation Problems topic in section One Dimensional Consolidation of Geotechnical Engineering I

Answer 1

Correct option is (a) ∆e=0.139∆H

Explanation: Given, Hf=13.45

ef=0.864

\(∆e=\frac{1+e_f}{H_f}  ∆H\)

\(∆e=\frac{1+0.864}{13.45} ∆H\)

∆e=0.139∆H.