Question

The difference in voids ratio ∆e of initial and increased pressure is given by __________

(a) \(∆e=log_{10}\frac{σ’_0+∆σ’}{σ’_0}\)

(b) \(∆e=C_c \frac{σ’_0+∆σ’}{σ’_0}\)

(c) \(∆e=C_c log_{10} \frac{σ’_0+∆σ’}{σ’_0}\)

(d) \(∆e=C_c log_{10}  \frac{σ’_0}{σ’_0} \)

This question was addressed to me during an interview for a job.

My question is from Consolidation Process topic in portion One Dimensional Consolidation of Geotechnical Engineering I

Answer 1

Correct answer is (c) \(∆e=C_c log_{10} \frac{σ’_0+∆σ’}{σ’_0}\)

The explanation is: The difference in voids ratio ∆e of initial and increased pressure is given by,

\(∆e=C_c log_{10}\frac{σ’_0+∆σ’}{σ’_0}, here ∆e=e_0-e.\)