Right choice is (b) \(\frac{∆H}{H_0} =\frac{e_o-e}{1+e_o}\)
The best explanation: When the soil is laterally confined, there is decrease in the volume. Since the soil is laterally confined, there will be change of volume only due to the decrease in the thickness which implies to the changes in volume is proportional to change in thickness ∆H. This is also true for the initial conditions.
∴ \(\frac{∆H}{H_0} = \frac{e_o-e}{1+e_o}\)
Where eo-e=∆e.