Question

The change in voids ratio of the consolidation test is calculated from the relation of________

(a) \(∆e=\frac{1+e_f}{2} ∆H\)

(b) \(∆e=\frac{1+e_f}{H_f}  ∆H_f\)

(c) \(∆e=\frac{1+e_f}{H}\)

(d) \(∆e=\frac{e_f}{H_f} ∆H\)

I got this question by my college professor while I was bunking the class.

I would like to ask this question from Calculation of Voids Ratio and Coefficient of Volume Change topic in division One Dimensional Consolidation of Geotechnical Engineering I

Answer 1

Correct choice is (a) \(∆e=\frac{1+e_f}{2} ∆H\)

Easiest explanation: The change in voids ratio with the pressure increment is given by the relation,

\(\frac{∆e}{1+e_f}=\frac{∆H}{H_f},\) therefore on rearranging the equation, we get,

\(∆e=\frac{1+e_f}{2} ∆H.\)