Right choice is (c) \(m_v=-\frac{∆H}{H_o} \frac{1}{∆σ’}\)
To elaborate: Since we know the relation of change in voids ratio with the pressure increment is given by the relation,
\(\frac{∆e}{1+e_0}=\frac{∆H}{H_0},\) and coefficient of volume change is given by \(m_v=-\frac{∆e}{1+e_o}\frac{1}{∆σ’}.\)
Therefore, from the two equations, we get,
\(m_v=-\frac{∆H}{H_o} \frac{1}{∆σ’}.\)