The correct answer is (b) 1.7778
Easiest explanation: Given,
dA=2/2 = 1cm
dB=3/2= 1.5 cm
\(\frac{t_B}{t_A} = \frac{4}{1}\)
The ratio of coefficient of consolidation is, \(\frac{(C_v)_A}{(C_v)_B} \)
\(\frac{(C_v)_A}{(C_v)_B} = \frac{(d_A)^2}{(d_B)^2} × \frac{t_B}{t_A} = \frac{(2/2)^2}{(3/2)^2} × \frac{4}{1}=1.7778.\)