Right choice is (c) 97 days
The explanation is: Given, single drainage for sample and double drainage for field layer,
t1 = 2 0 min
d1 = 24 mm = 2.4 cm
d2 = 2 m = 200cm
Since, for same degree of consolidation of 50%, Tv is same,
\(t∝\frac{d^2}{C_r}\)
Therefore, \(\frac{t_2}{t_1} =(\frac{d_2}{d_1})^2\)
So, \(t_2=t_1 (\frac{d_2}{d_1} )^2=20(\frac{200}{2.4})^2=97 \,days.\)