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A 2m mower is operating at 3.5 km/h with an overall efficiency of 75%. Calculate the area covered by it in ha/h.

(a) 0.525

(b) 0.625

(c) 0.725

(d) 0.825

I had been asked this question during an online exam.

This intriguing question comes from Harvesting Equipments in chapter Harvesting Equipments of Farm Machinery

1 Answer

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Best answer
Correct choice is (a) 0.525

Easiest explanation: Area covered=\(\frac{S*W*Ef}{10*1000}=\frac{3.5*2*75}{10*100}\) = 0.525 ha/h.

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