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The speed reduction in 1^st low gear of tractor box and differential with final drive are 5:1 and 45:1 for a tractor developing 30 KW at engine at an rpm of 2500 with overall efficiency of 85%. The torque is KN-m available at wheel axle?

(a) 15

(b) 21.50

(c) 24.55

(d) 36.50

I got this question in exam.

My doubt stems from Mechanical Power Transmission in section Mechanical Power Transmission of Farm Machinery

1 Answer

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The correct answer is (d) 36.50

Explanation: Naxle = 1500*\(\frac{1}{5}*\frac{1}{45}\) = 6.67 rpm

T=\(\frac{P*60}{2πN}=\frac{25500*60}{2π*6.67}\) = 36.50 KN-m.

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