+1 vote
in Farm Machinery by (38.9k points)
A 2-wheel drive 35 HP tractor has 1.5 m rear wheel diameter. The engine runs at 1200 rev/min. The total reduction of speed is 30:1. Find the travelling speed of the tractor in km/h and tractive force at each driving wheel.

(a) 3.896 KN

(b) 4.157 KN

(c) 7.437 KN

(d) 8.315 KN

The question was asked by my college director while I was bunking the class.

My doubt is from Tractor Classification and Details in chapter Lubrication System and Tractor’s Classification of Farm Machinery

1 Answer

+2 votes
by (243k points)
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Best answer
Correct answer is (b) 4.157 KN

Best explanation: Naxle = 1200/30 = 40 rpm

Velocity = πNa * Da

= π * 40/60 * 1.5 = 3.14 m/s

Tractive force = P/V = \(\frac{(35*0.746)}{3.14}\) = 8.315 KN

Tractive at each driving wheel = 8.315/ 2

= 4.157 KN.

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