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A tractor having weight as 1500 KGF is brought to a speed of 10 KMPH in 10 seconds by applying a uniform acceleration. Calculate initial fore on tractor.

(a) 416.67 N

(b) 372.98 N

(c) 747.8 N

(d) 219.84 N

The question was posed to me in quiz.

I need to ask this question from Tractor Classification and Details in chapter Lubrication System and Tractor’s Classification of Farm Machinery

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Best answer
The correct option is (a) 416.67 N

The explanation: Acceleration: \(\frac{v-u}{t}=\frac{10*5}{18}-\frac{0}{10}=\frac{50}{18*10}=\frac{5}{18}\)

Initial Force = ma

= 1500*\(\frac{5}{18}\)

= 416.67 N.

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