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A mower has drive wheel of 60 cm diameter. The crank of the mower makes 600 rev/min when it is driven by a tractor, moving at a speed of 2.3 km/hr. If the speed ratio between the crank wheel and land wheel is changed to 27:1, calculate the increase in speed of mower to maintain same speed of crank.

(a) 0.19 km/hr

(b) 0.67 km/hr

(c) 0.11 km/hr

(d) 0.21 km/hr

I got this question in an online quiz.

This question is from Harvesting Equipments topic in chapter Harvesting Equipments of Farm Machinery

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The correct option is (d) 0.21 km/hr

The explanation is: Revolution of the drive wheel = 600/27 = 22.2 rev/min

Linear speed of mower = π * \(\frac{60}{100}*\frac{60}{27}\)*60 m = 2.51 km/hr

Increase in speed of mower = 2.51-2.30 = 0.21 km/hr

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