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in Farm Machinery by (38.9k points)
A 20 teeth sprocket is operating at 150 rpm and driving a 43 teeth sprocket through a chain. The pitch of the chain is 250 mm and alternate strength is 10 KN. Determine the average torque applied to driven shaft at maximum power transmission.

(a) 10000 N

(b) 17105 N

(c) 15984 N

(d) 16156 N

The question was asked in an interview for job.

Query is from Mechanical Power Transmission topic in chapter Mechanical Power Transmission of Farm Machinery

1 Answer

+2 votes
by (243k points)
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Best answer
The correct choice is (b) 17105 N

To explain I would say: P = \(\frac{πD}{T} \)

D=\(\frac{0.25*43}{π}\) = 3.421 m

T=F*\(\frac{D}{2}\)=10*1000*\(\frac{3.421}{2}\) = 17105 N.

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