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Calculate the power transmitted by the belt and pulley arrangement, if tension on tight side of the belt is 50 kg and tension on slack side is 25 kg. The diameter and speed of driving pulley is 0.95 m and 350 rpm.

(a) 3.97 KW

(b) 4.97 KW

(c) 6.97 KW

(d) 5.97 KW

I had been asked this question in a job interview.

This interesting question is from Mechanical Power Transmission topic in section Mechanical Power Transmission of Farm Machinery

1 Answer

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Correct choice is (d) 5.97 KW

To elaborate: Power = (T1 – T2) * v

V = \(\frac{πDN}{60}=\frac{π*0.95*350}{60}\)=17.41 m/s

P = (490-147) * 17.41 = 5.97 KW.

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