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A counter shaft of engineering workshop is being driven by electric motor with the help of canvas belt and pulley arrangement such that the speed of belt is 600 m/min and it transmits 50 KW. What will be the difference between tensions on either side of the belt?

(a) 10000

(b) 100

(c) 5000

(d) 50

This question was posed to me in unit test.

This intriguing question originated from Power Transmission System in chapter Ignition and Power Transmission of Farm Machinery

1 Answer

+1 vote
by (243k points)
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Best answer
Right answer is (c) 5000

To explain: V = 600*10/60 = 10 m/s

P = (T1-T2) * V

50000 = (T1-T2) * 10

T1 – T2 = 5000

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