+1 vote
in Farm Machinery by (38.9k points)
A two-wheel drive tractor pulls an implement which requires a draft of 12.5 KN. The motion resistance of the tractor is 4.5 KN and the slip of the driver wheel is 20%. The transmission efficiency is 0.8. the percentage of power lost in converting engine power into drawbar power is ______

(a) 26.47%

(b) 36%

(c) 41.18%

(d) 52.94%

The question was posed to me in an international level competition.

The question is from Tillage in portion Tillage, Disc Plough & Numericals of Farm Machinery

1 Answer

+2 votes
by (243k points)
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Best answer
The correct choice is (d) 52.94%

The best explanation: According to figure

0.64x = 17; x=26.56

D=12.5 KN, R+4.5 KN, s=20%

P=12.5 + 4.5=17 KN; But useful pull is only 12.5 KN

Percent Loss = \(\frac{26.56-12.5}{26.56}\) *100 = 52.94%.

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