Question

Total draft of four bottom, 40cm Mb plough when ploughing 17.5 cm deep at 5.5 km/hr speed is 1700. Field efficiency is 75%. Calculate the actual power requirement.

(a) 24.73KW

(b) 25.45KW

(c) 23.39KW

(d) 22.41KW

This question was addressed to me in an interview.

I need to ask this question from Numericals on Mouldboard Plough topic in chapter Tillage, Disc Plough & Numericals of Farm Machinery

Answer 1

The correct option is (b) 25.45KW

To explain I would say: Unit Draft = \(\frac{Total \, draft}{Area} = \frac{1700}{4*40*17.5}\) = 0.607 kg/cm^2 *9.8 kPa = 59.48 kPa

Power requirement = \(\frac{1700*9.8*5.5*1000}{60*60}\)N.m/s = 25452.77 N.m/s = 25.45 KW.