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A 4-row animal drawn wheat seed drill with 300 mm row-to-row spacing is operated at 1.5 km/h. If the time loss, based on observed total time in seeding 1 ha arc is 15% in turning, 10% in seed filling and 10% in mechanical down time, then what is the field efficiency?

(a) 32%

(b) 40%

(c) 65%

(d) 74%

This question was addressed to me in final exam.

This interesting question is from Sowing Equipments topic in section Sowing Equipments of Farm Machinery

1 Answer

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Best answer
Right choice is (d) 74%

Explanation: Cth = \(\frac{1.2*1.5}{10}\) = 0.18 ha/h

Theoretical time required to cover 1 hectare of land = 1/0.18 = 5.5 h

Tt = 5.5*0.15 = 0.825 h

Ts = 5.5*0.10 = 0.55 h

Tm = 5.5*0.10 = 0.55 h

Field efficiency = \(\frac{To}{To+Tt+Ts+Tm}*100 = \frac{5.5}{5.5+0.825+0.55+0.55}\)*100 = 74 %.

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