Question

In case of immobilized enzymes, the equation \(V=K_L ([S_0]-[S])=\frac{V_{max} [S]}{K_m+S+\frac{S^2}{K_S}}\) represents ______________ inhibition.

(a) substrate

(b) product

(c) uncompetitive

(d) competitive

I have been asked this question by my college director while I was bunking the class.

My question is based upon Kinetics of Immobilized Enzymes topic in division Immobilized Enzymes Preparation and Kinetics of Enzyme Technology

Answer 1

Right answer is (a) substrate

The explanation: As compared to product inhibition, the equation is complicated for substrate inhibition and is given by \(V=K_L ([S_0 ]-[S])=\frac{V_{max} [S]}{K_m+S+\frac{S^2}{K_S}}\) where,

Vmax = max rate of reaction, S = Substrate concertation, S0 = initial substrate concentration, Km = Miachelis Menten constant, KL = Substrate mass transfer co-efficient, and Kp = Product inhibitory constant.

This equation is third order with respect to the micro-environmental substrate concentration.