An Internal combustion engine has a connecting rod of mass 2 kg and the distance between the centre of crank and centre of gudgeon pin is 25 cm. The Center of Gravity lies at a point 10 cm from the gudgeon pin along the line of centres. The radius of gyration of this system about an axis through the Center of Gravity perpendicular to the plane of rotation is 11 cm. Find the mass located at gudgeon pin in Kg.

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An Internal combustion engine has a connecting rod of mass 2 kg and the distance between the centre of crank and centre of gudgeon pin is 25 cm. The Center of Gravity lies at a point 10 cm from the gudgeon pin along the line of centres. The radius of gyration of this system about an axis through the Center of Gravity perpendicular to the plane of rotation is 11 cm. Find the mass located at gudgeon pin in Kg.

asked Sep 22, 2022 in Machine Dynamics by Grayson (34.3k points)

An Internal combustion engine has a connecting rod of mass 2 kg and the distance between the centre of crank and centre of gudgeon pin is 25 cm. The Center of Gravity lies at a point 10 cm from the gudgeon pin along the line of centres. The radius of gyration of this system about an axis through the Center of Gravity perpendicular to the plane of rotation is 11 cm. Find the mass located at gudgeon pin in Kg.

(a) 0.9

(b) 0.8

(c) 1.1

(d) 1.2

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This interesting question is from Correction Couple to be Applied to Make the Two Mass Systems Dynamically Equivalent topic in portion Inertia Forces in Reciprocating Parts of Machine Dynamics

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Fred · Answer 1 · 2022-10-14T11:52:43+0000

Correct option is (c) 1.1

For explanation: From the given data l = 25 cm, l1 = 10cm kg=11cm

l1.l2=kg^2, l2 = 12.1 cm

M= l2m/( l1+ l2)

= 12.1x 2/( 12.1 + 10)

= 1.1 Kg.

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