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A Porter governor has equal arms each of length 250 mm and pivoted on the axis of rotation. Each ball has a mass of 5 kg and the central load has a mass on the sleeve of 25 kg. The radius of rotation of the ball is 150 mm when the governor begins to lift and 200 mm when the governor is at maximum speed. Considering friction at the sleeve of 10N, find the power of the governor in N-m

(a) 447

(b) 44.7

(c) 4.47

(d) 5.0

This question was addressed to me in my homework.

Asked question is from Effort and Power of a Porter Governor topic in chapter Governors of Machine Dynamics

1 Answer

0 votes
by (38.6k points)
Right option is (c) 4.47

The explanation is: We know that the power of a governor is given by the relation

Power = governor effort x sleeve lift

= 57.4 x 0.1 N-m

= 5.74 N-m.

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