+1 vote
in Machine Dynamics by (34.3k points)
A Porter governor has equal arms each of length 250 mm and pivoted on the axis of rotation. Each ball has a mass of 5 kg and the central load has a mass on the sleeve of 25 kg. The radius of rotation of the ball is 150 mm when the governor begins to lift and 200 mm when the governor is at maximum speed. Neglecting friction at the sleeve, find the governor effort.

(a) 44.7 N

(b) 22.35 N

(c) 89.4 N

(d) 50 N

I have been asked this question in semester exam.

Asked question is from Effort and Power of a Porter Governor in portion Governors of Machine Dynamics

1 Answer

0 votes
by (38.6k points)
The correct option is (a) 44.7 N

Easy explanation: If c = Percentage increase in speed, then

cN1 = N2 – N1 = 25 rpm

c = 25/164 = 0.152

governor effort = c(m+M)g = 44.7 N.

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