A Porter governor has equal arms each of length 250 mm and pivoted on the axis of rotation. Each ball has a mass of 5 kg and the central load has a mass on the sleeve of 25 kg. The radius of rotation of the ball is 150 mm when the governor begins to lift and 200 mm when the governor is at maximum speed. Considering friction at the sleeve of 10N, find the range of speed in rpm.

Question

A Porter governor has equal arms each of length 250 mm and pivoted on the axis of rotation. Each ball has a mass of 5 kg and the central load has a mass on the sleeve of 25 kg. The radius of rotation of the ball is 150 mm when the governor begins to lift and 200 mm when the governor is at maximum speed. Considering friction at the sleeve of 10N, find the range of speed in rpm.

asked Sep 22, 2022 in Machine Dynamics by Grayson (34.3k points)

A Porter governor has equal arms each of length 250 mm and pivoted on the axis of rotation. Each ball has a mass of 5 kg and the central load has a mass on the sleeve of 25 kg. The radius of rotation of the ball is 150 mm when the governor begins to lift and 200 mm when the governor is at maximum speed. Considering friction at the sleeve of 10N, find the range of speed in rpm.

(a) 31.4

(b) 35.4

(c) 45.2

(d) 15.6

The question was posed to me by my school principal while I was bunking the class.

This intriguing question originated from Effort and Power of a Porter Governor topic in division Governors of Machine Dynamics

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Fred · Answer 1 · 2022-10-14T22:08:03+0000

The correct choice is (a) 31.4

To explain: When friction is taken into account

N1^2 = (mg+Mg-F)/mg x 895/h1

h1 = 0.2m

therefore N1 = 161 rpm

N2^2 = (mg+Mg+F)/mg x 895/h2

N2 = 192.4 rpm

Therefore range = 31.4 rpm.

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