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For the given data of an Internal combustion engine : Mass of parts = 180 kg bore = 175 mm, length of stroke = 200 mm, engine speed = 500 r.p.m., length of connecting rod = 400 mm and crank angle = 60° from T.D.C, find the inertia force.

(a) 17.56 N

(b) 19.2 N

(c) 18.53 N

(d) 18.00 N

This question was addressed to me in an online quiz.

The question is from Forces on the Reciprocating Parts of an Engine Neglecting Weight of the Connecting Rod topic in section Inertia Forces in Reciprocating Parts of Machine Dynamics

1 Answer

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by (38.6k points)
The correct option is (c) 18.53 N

The best explanation: Ratio of length of connecting rod and crank n = l/r = 2*200/(200÷2) = 4,

We know that inertia force is m.ω^2.r(cosθ + cos2θ/ n)

inserting values will give F = 18.53 N.

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