+1 vote
in Machine Dynamics by (34.3k points)
A V-twin engine has the cylinder axes at 90 degrees and the connecting rods operate a common crank. The reciprocating mass per cylinder is 11.5 kg and the crank radius is 7.5 cm. The length of the connecting rod is 0.3 m. If the engine is rotating at the speed is 500 r.p.m. What is the value of maximum resultant secondary force in Newtons?

(a) 736

(b) 836

(c) 936

(d) 636

This question was addressed to me in an internship interview.

Query is from Balancing of V-engines in chapter Balancing of Reciprocating Masses of Machine Dynamics

1 Answer

0 votes
by (38.6k points)
The correct answer is (b) 836

Explanation: Maximum resultant secondary force is given by the equation:

 \(\sqrt{2}\) (m/n)xω^2.r

substituting the values we get

Fsmax = 836 N.

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