If the mass of the reciprocating parts is doubled, then the primary force is halved.

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A V-twin engine has the cylinder axes at 90 degrees and the connecting rods operate a common crank. The reciprocating mass per cylinder is 23 kg and the crank radius is 7.5 cm. The length of the connecting rod is 0.3 m. If the engine is rotating at the speed is 500 r.p.m. What is the value of maximum resultant secondary force in Newtons?

asked Sep 23, 2022 in Machine Dynamics by Grayson (34.3k points)

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A V-twin engine has the cylinder axes at 90 degrees and the connecting rods operate a common crank. The reciprocating mass per cylinder is 11.5 kg and the crank radius is 7.5 cm. The length of the connecting rod is 0.3 m. If the engine is rotating at the speed is 500 r.p.m. What is the value of maximum resultant secondary force in Newtons?

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A V-twin engine has the cylinder axes at 90 degrees and the connecting rods operate a common crank. The reciprocating mass per cylinder is 34.5 kg and the crank radius is 7.5 cm. The length of the connecting rod is 0.3 m. If the engine is rotating at the speed is 500 r.p.m. What is the value of maximum resultant secondary force in kN?

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For a V-twin engine, which of the following means can be used to balance the primary forces?

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If c be the fraction of the reciprocating parts of mass m to be balanced per cyclinder of a steam locomotive with crank radius r, angular speed ω, distance between centre lines of two cylinders a, then the magnitude of the maximum swaying couple is given by

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What is the effect of partial balancing of the reciprocating parts?

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The secondary unbalanced force produced by the reciprocating parts of a certain cylinder of a given engine with crank radius r and connecting rod length l can be considered as equal to primary unbalanced force produced by the same weight having

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The effect of an unbalanced primary force along the line of stroke is to produce ________

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The effect of an unbalanced primary force perpendicular to the line of stroke is to produce _____

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The primary unbalanced force is maximum when the angle of inclination of the crank with the line of stroke is

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The crank-pin circle radius of a horizontal engine is 300 mm. The mass of the reciprocating parts is 250 kg. When the crank has travelled 30° from T.D.C., the difference between the driving and the back pressures is 0.45 N/mm^2. The connecting rod length between centres is 1.2 m and the cylinder bore is 0.5 m. If the engine runs at 250 r.p.m. and if the effect of piston rod diameter is neglected, calculate the net load on piston.

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If the connecting rod is not too long, then which of the following phenomenon occurs?

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When the connecting rod is too long, secondary forces arise due to reciprocating masses.

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Piston diameter = 0.24 m, length of stroke = 0.6 m, length of connecting rod = 1.5 m, mass of reciprocating parts = 300 kg, mass of connecting rod = 250 kg; speed of rotation = 125 r.p.m; centre of gravity of connecting rod from crank pin = 0.5 m ; Kg of the connecting rod about an axis through the centre of gravity = 0.65 m Find the equivalent length L of a simple pendulum swung about an axis.

asked Sep 22, 2022 in Machine Dynamics by Grayson (34.3k points)

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In a multicylinder inline engine, each imaginary secondary crank with a mass attached to the crankpin is inclined to the line of stroke at which angle?

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Tractive force attains a maxima or minima when the crank angle is 90 degrees.

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Tractive force is produced due to unbalanced forces perpendicular to the line of stroke of action.

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The resultant unbalanced force due to the two cylinders, along the line of stroke, is known as ______

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Hammer blow is along the line of stroke of the unbalanced force.

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