Correct answer is (c) 16.7 rad/s
The explanation: Given: d = 300 mm or r = 150 mm = 0.15 m ; m = 5 kg ; l = 600 mm = 0.6 m ;
N = 300 r.p.m. or ω = 2π × 300/60 = 31.42 rad/s
We know that the mass moment of inertia of the disc, about an axis through its centre of gravity and perpendicular to the plane of disc,
I = m.r^2/2 = 5(0.15)^2/2 = 0.056 kg-m^2
and couple due to mass of disc, C = m.g.l = 5 × 9.81 × 0.6 = 29.43 N-m
Let ωP = Speed of precession
We know that couple (C),
29.43 = I.ω.ωP = 0.056 × 31.42 × ωP = 1.76 ωP
ωP = 29.43/1.76 = 16.7 rad/s