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A uniform disc of diameter 300 mm and of mass 5 kg is mounted on one end of an arm of length 600 mm. The other end of the arm is free to rotate in a universal bearing. If the disc rotates about the arm with a speed of 300 r.p.m. clockwise, looking from the front, with what speed will it precess about the vertical axis?

(a) 14.7 rad/s

(b) 15.7 rad/s

(c) 16.7 rad/s

(d) 17.7 rad/s

I got this question in an international level competition.

The query is from Effect of Gyroscopic Couple on an Aeroplane topic in section Gyroscopic Couple and Precessional Motion of Machine Dynamics

1 Answer

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by (38.6k points)
Correct answer is (c) 16.7 rad/s

The explanation: Given: d = 300 mm or r = 150 mm = 0.15 m ; m = 5 kg ; l = 600 mm = 0.6 m ;

N = 300 r.p.m. or ω = 2π × 300/60 = 31.42 rad/s

We know that the mass moment of inertia of the disc, about an axis through its centre of gravity and perpendicular to the plane of disc,

I = m.r^2/2 = 5(0.15)^2/2 = 0.056 kg-m^2

and couple due to mass of disc, C = m.g.l = 5 × 9.81 × 0.6 = 29.43 N-m

Let ωP = Speed of precession

We know that couple (C),

29.43 = I.ω.ωP = 0.056 × 31.42 × ωP = 1.76 ωP

ωP = 29.43/1.76 = 16.7 rad/s

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