The number of degrees of freedom of a planar linkage with 8 links and 9 simple revolute joints is

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The number of degrees of freedom of a planar linkage with 8 links and 9 simple revolute joints is

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Greg · Answer 1 · 2022-10-18T22:40:04+0000

The correct choice is (c) 3

Easiest explanation: Given l= 8, j= 9

We know that, Degree of freedom,

n =3(l − 1)−2j = 3(8 − 1)−2 x 9 = 3.

The number of degrees of freedom of a planar linkage with 8 links and 9 simple revolute joints is

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