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The total number of instantaneous centers for a mechanism of n links is

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+1 vote
in Machine Kinematics by (38.0k points)
The total number of instantaneous centers for a mechanism of n links is

(a) n(n – 1)/2

(b) n

(c) n – 1

(d) n(n – 1)

The question was asked in an internship interview.

Origin of the question is Properties of Instantaneous Centre in division Velocity in Mechanisms of Machine Kinematics

1 Answer

0 votes
by (106k points)
The correct choice is (a) n(n – 1)/2

Easy explanation: The number of pairs of links or the number of instantaneous centres is the number of combinations of n links taken two at a time. Mathematically, number of instantaneous centres,

N = n(n – 1)/2.

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