+1 vote
in Machine Kinematics by (38.0k points)
The lengths of the links of a 4-bar linkage with revolute pairs are p,q,r, and s units. given that p<q<r<s. Which of these links should be the fixed one, for obtaining a “double crank” mechanism ?

(a) link of length p

(b) link of length q

(c) link of length r

(d) link of length s

I have been asked this question in an international level competition.

Asked question is from Velocity of a point Link on a Link By Instanteneous Centre Method topic in section Velocity in Mechanisms of Machine Kinematics

1 Answer

0 votes
by (106k points)
Right answer is (a) link of length p

The best I can explain: Given p<q<r<s

“Double crank” mechanism occurs, when the shortest link is fixed. From the given pairs p is the shortest link. So, link of length p should be fixed.

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