+1 vote
in Machine Kinematics by (38.0k points)
In a reverted gear train, two gears P and Q are meshing, Q-R is a compound gear, and R and S are meshing. The modules of P and R are 4 mm and 5 mm respectively. The numbers of teeth in P, Q and r are 20, 40 and 25 respectively. The number of teeth in S is

(a) 23

(b) 35

(c) 50

(d) 53

I got this question in examination.

Query is from Law of Gearing in portion Toothed Gearing & Gear Trains of Machine Kinematics

1 Answer

0 votes
by (92.2k points)
Right answer is (a) 23

Easiest explanation: C = 1/2m1(zp + zq) = 1/2m2(zr + zs)

   4(20 + 40) = 5(25 + zs)

   zs = 23.

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