+1 vote
in Machine Kinematics by (38.0k points)
In a single link robotic arm the end-effector slides upward along the link with a velocity of 0.5 m/s while the link rotates about revolute joint with an angular speed of 1 rad/sec. When the end-effector is at a distance of 1 m from the joint, the acceleration experienced by the end-effector will be

(a) 1 m/s^2

(b) 1.41 m/s^2

(c) 1.71 m/^2

(d) 2 m/^2

This question was addressed to me in an online quiz.

My doubt stems from Velocities in a Slider Crank Mechanism and Motion of a Link topic in chapter Velocity in Mechanisms of Machine Kinematics

1 Answer

0 votes
by (106k points)
The correct answer is (a) 1 m/s^2

Easy explanation: a = 2ωV = 2 x 1 x 0.5 = 1 m/s^2.

Related questions

We welcome you to Carrieradda QnA with open heart. Our small community of enthusiastic learners are very helpful and supportive. Here on this platform you can ask questions and receive answers from other members of the community. We also monitor posted questions and answers periodically to maintain the quality and integrity of the platform. Hope you will join our beautiful community
...