+1 vote
in Machine Kinematics by (38.0k points)
The piston of an engine moves with SIMPLE HARMONIC MOTION. The crank rotates at a speed of 120 r.p.m. with a stroke of 2 metres. Find the velocity of the piston in m/s^2, when it is at a distance of 0.75 metre from the centre.

(a) 118.46

(b) 117.33

(c) 128.41

(d) 119.02

The question was posed to me in an internship interview.

I want to ask this question from Differential Equation of Simple Harmonic Motion topic in portion Simple Harmonic Motion of Machine Kinematics

1 Answer

0 votes
by (106k points)
Right option is (a) 118.46

To elaborate: When a body is undergoing SIMPLE HARMONIC MOTION, its acceleration is given by the equation

a=ω^2x

substituting the values we get

a = 118.46 m/s^2

Related questions

We welcome you to Carrieradda QnA with open heart. Our small community of enthusiastic learners are very helpful and supportive. Here on this platform you can ask questions and receive answers from other members of the community. We also monitor posted questions and answers periodically to maintain the quality and integrity of the platform. Hope you will join our beautiful community
...