+1 vote
in Machine Kinematics by (38.0k points)
If V is the maximum velocity of a body undergoing SIMPLE HARMONIC MOTION, then what is the average velocity of motion from one extreme to other extreme is?

(a) 2V/π

(b) 4V/π

(c) V/2π

(d) 2V/3π

I got this question in exam.

Asked question is from Differential Equation of Simple Harmonic Motion in chapter Simple Harmonic Motion of Machine Kinematics

1 Answer

0 votes
by (106k points)
Right choice is (a) 2V/π

To explain: V = 2πA/T

V av = 2A/T÷2  = 4A/T

A/T = V/2π

Vav = 2V/π

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