+1 vote
in Machine Kinematics by (38.0k points)
The piston of an engine moves with SIMPLE HARMONIC MOTION. The crank rotates at a speed of 120 r.p.m. with a stroke of 2 metres. Find the velocity of the piston in m/s, when it is at a distance of 0.75 metre from the centre.

(a) 8.31

(b) 7.33

(c) 8.41

(d) 9.02

This question was addressed to me in homework.

The doubt is from Differential Equation of Simple Harmonic Motion in section Simple Harmonic Motion of Machine Kinematics

1 Answer

0 votes
by (106k points)
The correct choice is (a) 8.31

Easiest explanation: When a body is undergoing SIMPLE HARMONIC MOTION, its velocity is given by the equation

\(v = \omega \sqrt{(A^2-x^2)}\)

substituting the values we get

v = 8.31 m/s.

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