+1 vote
in Machine Kinematics by (38.0k points)
The piston of a steam engine moves with simple harmonic motion. The crank rotates at 120 r.p.m. with a stroke of 2 metres. Find the velocity of the piston, when it is at a distance of 0.75 metre from the centre.

(a) 8 m/s

(b) 8.31 m/s

(c) 9 m/s

(d) none of the mentioned

The question was asked in class test.

This intriguing question comes from Centre of Percussion in chapter Simple Harmonic Motion of Machine Kinematics

1 Answer

0 votes
by (106k points)
Right choice is (b) 8.31 m/s

The best explanation: Given : N = 120 r.p.m. or ω = 2π × 120/60 = 4π rad/s ; 2r = 2 m or r = 1 m;

x = 0.75 m

Velocity of the piston

We know that velocity of the piston,

v = ω√r^2 – x^2 = 4π√1 – (0.75)^2 = 8.31 m/s.

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