+1 vote
in Machine Kinematics by (38.0k points)
In a slider-crank mechanism, the crank is rotating with an angular velocity of 20 rad/s in counterclockwise direction. At the instant when the crank is perpendicular to the direction of the piston movement, velocity of the piston is 2 m/s. Radius of the crank is

(a) 100 cm

(b) 10 cm

(c) 1 cm

(d) 0.1 cm

I got this question by my college professor while I was bunking the class.

My doubt stems from Velocities in a Slider Crank Mechanism and Motion of a Link topic in portion Velocity in Mechanisms of Machine Kinematics

1 Answer

0 votes
by (106k points)
Correct option is (b) 10 cm

Explanation: Vp = ωr(sinϴ + sin2ϴ/2n)

In this case ϴ = 90^0

Vp = ωr

r = Vp/ω = 2/20 = 0.1 m or 10 cm.

Related questions

We welcome you to Carrieradda QnA with open heart. Our small community of enthusiastic learners are very helpful and supportive. Here on this platform you can ask questions and receive answers from other members of the community. We also monitor posted questions and answers periodically to maintain the quality and integrity of the platform. Hope you will join our beautiful community
...