+1 vote
in Machine Kinematics by (38.0k points)
In a slider crank mechanism, the crank rotates with a constant angular velocity of 300 rpm, Length of crank is 150mm, and the length of the connecting rod is 600mm. Determine linear velocity of the midpoint of the connecting rod in m/s. Crank angle = 45° from IDC.

(a) 4.1

(b) 4.4

(c) 4.8

(d) 5.2

This question was posed to me in an online interview.

I'd like to ask this question from Acceleration in the Slider Crank Mechanism & Coriolis Component in chapter Acceleration in Mechanisms of Machine Kinematics

1 Answer

0 votes
by (106k points)
Correct option is (a) 4.1

The explanation is: Let the Intersection point of crank and connecting rod be termed as ‘x’

velocity of x = ωxL(crank)

= 4.713 m/s

We draw a corresponding velocity diagram for the same,

where this velocity is perpendicular to the crank, this diagram when drawn to scale turns out to be a triangle.

From the reference point we can measure the velocity of midpoint of connecting rod

V = 4.1 m/s.

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