Right option is (b) 0.20
For explanation: If the boy slides back, the horse could not exert a
friction of 60 N on the boy. The maximum force of static
friction that the horse may exert on the boy is
fs = μs = μsMg
μs(30 kg) (10m/s^2) = μs 300 N
where μs is the coefficient of static friction. Thus,
μs(300 N) <60 N
or, μs <60/300 = 0.20.